CodeForces.com is the web site, which shows problems for competitive programmers. Today I have decided to take a look at the 2. problem of the 2. division of Round 424 –Keyboard Layouts.
The problem is pretty simple to explain for everyone, who has other keyboard except for the standard QWERTY one. Pretty much, there is a person, who has two keyboard layouts, he writes something on the wrong one and wants automatic translation to the correct one. This is the explanation of the problem in CF:
There are two popular keyboard layouts in Berland, they differ only in letters positions. All the other keys are the same. In Berland they use alphabet with 26 letters which coincides with English alphabet.
You are given two strings consisting of 26 distinct letters each: all keys of the first and the second layouts in the same order.
You are also given some text consisting of small and capital English letters and digits. It is known that it was typed in the first layout, but the writer intended to type it in the second layout. Print the text if the same keys were pressed in the second layout.
Since all keys but letters are the same in both layouts, the capitalization of the letters should remain the same, as well as all other characters.
The first line contains a string of length 26 consisting of distinct lowercase English letters. This is the first layout.
The second line contains a string of length 26 consisting of distinct lowercase English letters. This is the second layout.
The third line contains a non-empty string s consisting of lowercase and uppercase English letters and digits. This is the text typed in the first layout. The length of s does not exceed 1000.
Print the text if the same keys were pressed in the second layout.
What have I done? Initially, I thought about reading the two layouts and writing them in a dictionary, then checking whether there is an uppercase letter, lowering it and looking to a dictionary, then returning the value to upper. After 1 minute, looking how the code looks like I have decided that it is not a good idea to put so many if-s and it is a better idea simply to write the char to upper value in a dictionary again. Thus, within about 15 minutes, the problem was solved by the following code:
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using System; using System.Collections.Generic; class KeyboardLayouts { static void Main() { string str1 = Console.ReadLine(); string str2 = Console.ReadLine(); string strText1 = Console.ReadLine(); string strResult = ""; Dictionary<char, char> dictM = new Dictionary<char, char>(); for (int i = 0; i < 26; i++) { dictM.Add(str1[i], str2[i]); dictM.Add(char.ToUpper(str1[i]), char.ToUpper(str2[i])); } foreach (char chItem in strText1) { if (char.IsDigit(chItem)) { strResult += chItem; } else { strResult += dictM[chItem]; } } Console.WriteLine(strResult); } } |
Cheers!