CodeForces has people working 24/7, trying to come up with interesting problems for the IT community. Thus, it’s always challenging to take a look at these problems and to try to solve them.

The latest problem I have faced was one for a stack and reordering of one. Pretty much like this:

*Okabe and Super Hacker Daru are stacking and removing boxes. There are n boxes numbered from 1 to n. Initially there are no boxes on the stack.*

*Okabe, being a control freak, gives Daru 2n commands: n of which are to add a box to the top of the stack, and n of which are to remove a box from the top of the stack and throw it in the trash. Okabe wants Daru to throw away the boxes in the order from 1 to n. Of course, this means that it might be impossible for Daru to perform some of Okabe’s remove commands, because the required box is not on the top of the stack.*

*That’s why Daru can decide to wait until Okabe looks away and then reorder the boxes in the stack in any way he wants. He can do it at any point of time between Okabe’s commands, but he can’t add or remove boxes while he does it.*

*Tell Daru the minimum number of times he needs to reorder the boxes so that he can successfully complete all of Okabe’s commands. It is guaranteed that every box is added before it is required to be removed.*

*Input*

*The first line of input contains the integer n (1 ≤ n ≤ 3·10 ^{5}) — the number of boxes.*

*Each of the next 2n lines of input starts with a string “add” or “remove“. If the line starts with the “add“, an integer x (1 ≤ x ≤ n) follows, indicating that Daru should add the box with number x to the top of the stack.*

*It is guaranteed that exactly n lines contain “add” operations, all the boxes added are distinct, and n lines contain “remove” operations. It is also guaranteed that a box is always added before it is required to be removed.*

*Output*

*Print the minimum number of times Daru needs to reorder the boxes to successfully complete all of Okabe’s commands.*

What do we do? As you can see, Daru is allowed to rebuild the whole stack, once there is a need to. Thus, its a bit meaningless to keep a track of how the stack is rebuilt. After all, Daru is quite a clever person (probably) and does the work for us 🙂 That’s why we are allowed to clear the stack on the first mistake and keep just a track of the requests, using the counter++. No meaningless sorting are resorting, it does not bring us anything, we just want the count of the times the stack is reordered. And we get it by incrementing the result variable every time we clear the stack. The solution looks like this:

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using System; using System.Collections; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading.Tasks; class Startup { static void Main() { int n = int.Parse(Console.ReadLine()); var stStack = new Stack(n); int result = 0; int counter = 1; for (int i = 0; i < n*2; i++) { string [] strInput = Console.ReadLine().Split().ToArray(); if (strInput.Count() > 1) { stStack.Push(int.Parse(strInput[1])); } else { if (stStack.Count()>0) { if (stStack.Peek() == counter) { stStack.Pop(); } else { stStack.Clear(); result++; } } counter++; } } Console.WriteLine(result); } } |

Enjoy it! 🙂