Last Sunday I was taking part in Basic Java Exam at the SoftUni. I managed to get 130 points (out of 400) and thus to be somewhere in top 50% of the participants. I had 100 points at this problem, and somehow I made 20 points at a problem, asking you to make a simple program, which calculates strings. The 20 points were mainly from code refactoring, found in Stack Overflow, in which I was quite lucky to find some samples. Anyway, JavaScript libraries were not allowed to be included and thus I had to give my best on Sunday, which resulted in 20% of the tests.

So, the Simple Expression asks you to create a code, which calculates string. Problem 3 from here.

How to do it? The worst part is that you do not know how many numbers you are going to sum – that was the reason why I got only 20% of the correct results. In order to define this, a clever idea is to count the operators in the expression – if you have 6 operators, the numbers are 7 and so on. A second problem for me was the BigDecimal type in Java – I simply was not aware of it đź™‚ In order to save you from more lame excuses, I will present the original code here:

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import java.math.BigDecimal; import java.util.Scanner; public class SimpleExpression { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); String expression = scanner.nextLine(); expression = expression.replace(" ", ""); String[] numbers = expression.split("[^0-9.]+"); String[] operators = expression.split("[0-9.]+"); BigDecimal sum = new BigDecimal(numbers[0]); for (int i = 1; i < operators.length; i++) { BigDecimal number = new BigDecimal(numbers[i]); if (operators[i].equals("+")) { sum = sum.add(number); } else if (operators[i].equals("-")) { sum = sum.subtract(number); } else { throw new IllegalArgumentException( "Invalid operator: " + operators[i]); } } System.out.println(sum.toPlainString()); } } |

What it does?

- The string
**expressionÂ**reads the line; - Then we simply replace the space with nothing;

- The arraysÂ
**numbers**andÂ**operators**areÂ filled with regular expressions (quite a good move!); - The first number in the array
**numbers**is allocated to the BigDecimal**sum**; - Then for every position in the array of the operators we run a loop;
- In the loop we declare a BigDecimal
**numberÂ**and we assign value from the arrayÂ**numbersÂ**to it; - Then we have two options, depending on the operator – to add or to subtract this number from the sum;
- At the end, we print the sum with theÂ
*.toPlainString()Â*function.

Pretty much, when you see it written down, it is really easy. What was hard for me at the exam was that I was thinking that it should be done a little weird – starting from the back and then reading the numbers and performing calculations until we reach the first one, which always should be added – e.g. if we have “5+6+8-9”, then I would do the following – “0-9+8+6” and then always make sure that I add 5 at the end. Anyway, the idea is doable, but the fact that I did not know the Java syntax quite well (or at all) at that time was the reason I had only 20% at this problem.

Enjoy it!